Question

A stretched bungie cord has 120,000 J of stored energy and a spring constant of 8, 000N / m , how much distance was it stretched?​

Answer 1

Answer:

$e.p.e = \frac{1}{2} k {x}^{2}$

in this formulae

EPE= elastic potential energy

k = spring constant

x = distance

Explanation:

so using the above equation easily we can find the answer therefore

$120000 = \frac{1}{2} \times 8000 \times {x}^{2} \\ 120000 = 4000 \times {x}^{2} \\ \frac{120000}{4000} = {x}^{2} \\ \sqrt{30} = x \\ x = 5.47m$