Question

a stretched string of length 4m vibrates into 6 loops, the distance between consecutive antinodes is
​

Answer 1

Answer:

0.2m

In fifth overtone there are 6 loops and each loop has length of half wavelength.

⟹6

2

λ

=L=2.4m

⟹λ=0.8m

Now, distance between successive node and antinode=

4

λ

=0.2m

Hence, answer is option-(B).

Answer 2

Answer:

The above given answer is wrong . Dont rely on it

Explanation:

The correct answer is 2/3

d = l/6 = 4/6 = 2/3 m

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