Question

A stretched string with tension of 20n and mass per unit length 5gm/cm is vibrating with frequency 20 hz calculate mininum length of string

Answer 1

Hey dear,

◆ Answer-
l = 15.8 cm

◆ Explaination-
# Given-
T = 20 N
μ = 5 gm/cm = 0.5 kg/m
f = 20 Hz

# Solution-
Velocity of wave on stretched string is given by-
v = √(T/μ)
v = √(20/0.5)
v = √40
v = 6.325 m/s

Minimum length of string can be -
l = λ/2
l = v / 2f
l = 6.325 / 2×20
l = 0.158 m = 15.8 cm

Therefore, minimum length of string is 15.8 cm.

Hope it helps you...