A string 1 m long having mass of 4 g is fixed fixed at both ends is under pressure of 160 N the frequency of fundamental mode is
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Answer:
μ=
l
m
=
25×10
−2
2.5×10
−3
=10
−2
Kg/m
1 st overtone ,
λ
s
=25cm=0.25m
f
s
=
λ
s
1
μ
T
=
0.25
1
10
−2
T
Pipe in fundamental frequency ,
4
λ
=40
λ
p
=160cm=1.6m
f
p
=
λ
p
v
=
1.6
320
f
s
−f
p
=8
4
10
−2
T
−
1.6
320
=8
T×10
2
=52
T=2704×10
−2
=27.04N
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