Question

A string 1 m long is drawn by a 300 hz vibrator attached to its end. The string vibratesin 3 segments . Yhe speed of transverse wave is

Answer 1

Answer:

200 m/s

Explanation:

λ = 2 L where λ - Wavelength , L - Length of segment or number of segments

So the speed of transverse wave = Velocity v = f λ = 300 x  2 / 3 = 200 m/s

So the speed of transverse wave = 200 m/s

Answer 2

length of string , L = 1m

frequency applied in the string , f = 300Hz

a/c to question, The string is vibrating in 3 segment as shown in figure.

so, $\frac{\lambda}{2}+\frac{\lambda}{2}+\frac{\lambda}{2}=L$

or, $\frac{3\lambda}{2}=L$

or, $\lambda=\frac{2L}{3}$

hence, wavelength, $\lambda$ = 2×1/3 = 2/3 m

now, velocity of transverse wave = wavelength × frequency

= 2/3 × 300 = 200 Hz