Physics, asked by mayurigaydhan, 1 month ago

A string 105 cm long is fixed at one end.the other end of string is moved up and down with frequency 15Hz A stationary wave produced in the string consist of 3 loops calculate the speed of progressive waves which have produced the stationary wave in the string​

Answers

Answered by grewalgurdeepsingh97
15

Answer:

There are 5 loops in 10 metre.

Length of one loop =2m

Length of two loops =2×2=4m

Now, λ=4m;v=20m/sec

From formula, v=vλ.⇒20=v×4⇒v=5Hz

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Answered by brokendreams
4

Step by step explanation:

Given: String of 105cm and Frequency is 15Hz.

To find: The speed of progressive waves.

For calculation of wavelength or 'λ',

We know that l=105cm=3 loops,

l=3\frac{λ}{2}

λ = \frac{2}{3} l

\frac{2}{3} × 105

70 cm=0.70 m

For calculation of speed,

We know that v = n × λ

v=15 × 0.70

10.50 m/s

The speed of the progressive waves is 10.50 Hz m/s.

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