A string 105 cm long is fixed at one end.the other end of string is moved up and down with frequency 15Hz A stationary wave produced in the string consist of 3 loops calculate the speed of progressive waves which have produced the stationary wave in the string
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Answer:
There are 5 loops in 10 metre.
Length of one loop =2m
Length of two loops =2×2=4m
Now, λ=4m;v=20m/sec
From formula, v=vλ.⇒20=v×4⇒v=5Hz
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Step by step explanation:
Given: String of and Frequency is .
To find: The speed of progressive waves.
For calculation of wavelength or 'λ',
We know that loops,
⇒
⇒
⇒ ×
⇒
For calculation of speed,
We know that × λ
⇒ ×
⇒
The speed of the progressive waves is .
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