Question

A string ABCD is suspended from two fixed points A and D. It carries two weights of 800 N and W at B and C

respectively. The inclination of DC to vertical is 600 and AB is 300. Angle ABC is 1500. Find the tension in

different parts of the string and magnitude of W​

Answer 1

Answer:

First string ABCD is split in to two parts, and consider the joints B and C separately Let, T1 = Tension in String AB. T2 = Tension in String BC T3 = Tension in String CD Since at joint B there are three forces are acting. SO Apply lamis theorem at joint B, T1/sin 60° = T2/sin 150° = 1000/sin 150° T1 = {sin 60° × 1000}/sin 150° = 1732 N T2 = {sin150° × 1000}/sin 150° = 1000N Again Apply lamis theorem at joint C, T2/sin 120° = T3/sin 120° = 1000/sin 120° T3 = {sin 120° × 1000}/sin 120° = 1000NRead more on Sarthaks.com - https://www.sarthaks.com/507174/string-abcd-attached-two-fixed-points-and-has-two-equal-weight-of-1000n-attached-to-it-at-and