Question

A string can bear a maximum tension of 3.16 kg-wt.what maximum number of revolutions per sec can be made by stone of mass 49 g tied to one end of 1 m long

Answer 1

T = maximum tension force in the string = 3.16 kg.wt = 3.16 x 9.8 N = 31 N

m = mass of tsone tied to string end = 49 g = 0.049 kg

r = length of the string = radius of the circle = 1 m

w = maximum angular

Tension force in the string provides the necessary centripetal force for the stone to move in circle

hence tension force =- centripetal force

T = m r w²

inserting the values

31 = (0.049) (1)  w²

w = 25.2 rad/s

1 rev = 6.28 rad

w = (25.2) (rad/s) (1 rev/6.28 rad)

w = 4.01 rev/s

Answer 2

Answer:

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