Question

A string can withstand of 25N what is the greatest speed at which a body of mass 1kgcan be whirled in horizontal circle using 1mlength of the string

Answer 1

Hey mate ^_^

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Answer:
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Centripetal force = Tension in the string

Maximum speed is v. 

Then, 

Maximum tension is $25N$

$25 = \frac{mv ^{2} }{r }$

$v ^{2} = \frac{25 \times 1}{1} = 25$

$v = 5m/s$

#Be Brainly❤️

Answer 2

hey

here is answer

Centripetal force = Tension in the string 

Maximum speed is v. 

Then, 

Maximum tension is 25N

$25 = \frac{mv ^{2} }{r}$

$v ^{2} = \frac{25 \times 1}{1}$

v = 5m/s

hope it helps

thanks