A string diameter is 1mm is kept on a table in the shape close flat spiral , a spiral with no gap between turns.the area of the table occupied by spiral is 1msquare.then the length of the string is
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Given A string diameter is 1 mm is kept on a table in the shape close flat spiral , a spiral with no gap between turns.The area of the table occupied by spiral is 1 m square. then the length of the string is
- Given A string is placed on a table. It resembles the shape of a close flat spiral and there is no gap in between the turns..
- Now the area occupied by the spiral is given as 1 m^2 and the diameter of a string is 1 mm = 1 x 10^-3 m
- The total spiral can be made pulled and made it straight to form a straight line which forms a horizontal straight line.
- Let the length be l
- So the total horizontal area will be length x diameter
- Area = l x d
- 1 m^2 = l x 1 x 10^-3 m
- Or 10^-3 m x l = 1 m^2
- Or l = 1m^2 / 10^-3 m
- Or l = 10^3 m
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