Question

A string has length 50 cm and area of cross section 30 cmsquare If a mass of 200 g is attached to the lower end of the string and it is whirled round at the rate of 50 ros in a circle of radius 53 cm Calculate the Young Modulas of string​

Answer 1

Answer:

Given ,

L = 49 cm

l = 51 cm - 49 c = 2 cm

Cross sectional area = 20 mm^{2}mm

2

= 0.2 cm^{2}cm

2

,

mass (m) = 100 g , R = 51 cm

ω = 40 r.p.s = 80 π rad·sec^{- 1}sec

−1

When the mass attached to the string is whirled, the length of the string increases under the effect of centrifugal force.

The centrifugal force, F = mRω^{2}ω

2

= 100 x 51 x (80 π)^{2}(80π)

2

Answer 2

Answer:

Area of the field

= Area of upper triangle + Area of Lower triangle

= 1/2 × 13 × 24 + 1/2 × 8 × 24

= 156 + 96 = 252 m²

I hope this will be help you.