Question

A string is tied around a rectangular packet 35cm by 25cm with an overlapping of 8cm. What is the length of the string used?

Answer 1

Answer:

Area of Rectangle= L*B....

Area= 35*25=875cm^2...

for overlapping = 875*8= 7000

Answer 2

Answer:

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128cm

Step-by-step explanation:

Length and breadth of rectangular packet = 35cm and 25cm respectively

The string is wrapped around the rectangular packet. That means we need to find the perimeter of the packet

Perimeter of rectangular packet = 2(l+b)

⇒ 2(35+25)cm= 120cm

Then it had a overlapping of 8cm = (120+8) = 128cm