a string is vibrating in its fifth overtone between two rigid supports of 1.8m apart , what is the distance between successive nodes? please answer
Answers
----> As the string is between two rigid supports which are 1.8m apart..
Hence, the wavelength of the string , can be considered as 1.8m
☞Now ,we know that the distance between the 2 successive nodes is one half of the wavelength .
Therefore, distance between two successive nodes is 1.8/2 = 0.9m ✓✓
Hope it helps... ^_^
Concept:
Half of the wavelength separates two subsequent nodes from one another. It is expressed as, d = λ/2
Given:
The separation between two rigid supports = 1.8m
The vibration of overtone = 5th
Find:
We need to determine the distance between the two successive nodes.
Solution:
A standing wave's node is the location along its length when its amplitude is at its smallest.
When there is the presence of the 5th overtone, there must be 6 loops and each loop should correspond to half the length of wavelength.
Therefore, the formula becomes,
6×λ/2 = L where L is the distance between two rigid supports, λ is the wavelength and 6 is the number of loops.
Therefore, L = 6 × λ/2
1.8 = 6 × λ/2
λ = (1.8 × 2) / 6
λ = 0.6m
We know, that the difference between two successive nodes is expressed as- d = λ/2
Therefore, d = 0.6/2
d = 0.3m
Thus, the distance between successive nodes is 0.3m.
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