Question

A string of length 0.5 m carries a bob with a period √2s. Calculate angle of inclination of string with vertical and tension in the string.(Ans : 9° 5', 0.9900 N)

Answer 1

Dear Rujith,

◆ Answer -

θ = 9.9°

T = 0.9948 N

◆ Explanation -

Period of the string is calculated as -

T = 2π√(lcosθ/g)

√2 = 2π√(0.5×cosθ/9.8)

√2/2π = √(cosθ/19.6)

19.6/2π^2 = cosθ

cosθ = 0.9929

θ = 9.9°

Tension in the string is calculated by -

T = mg / cosθ

T = 0.1 × 9.8 / cos9.9

T = 0.98 / 0.9851

T = 0.9948 N

Therefore, angle of inclination is 9.9° and tension is 0.9948 N.

Thanks dear.