A string of length 0.5 m carries a bob with a
period root 2s. Calculate angle of inclination of
string with vertical and tension in the string
Answers
Answered by
2
Answer:
θ = 9.9°
T = 0.9948 N
Step-by-step explanation:
Period of the string is calculated as -
T = 2π√(lcosθ/g)
√2 = 2π√(0.5×cosθ/9.8)
√2/2π = √(cosθ/19.6)
19.6/2π^2 = cosθ
cosθ = 0.9929
θ = 9.9°
Tension in the string is calculated by -
T = mg / cosθ
T = 0.1 × 9.8 / cos9.9
T = 0.98 / 0.9851
T = 0.9948 N
Therefore, angle of inclination is 9.9° and tension is 0.9948 N.
Hope it helped you mate!!
Similar questions