Question

A string of length 1 m is fixed at one end and carries a mass 100g at the other end. The string makes 2/pi revolutions per second around a vertical axis through fixed end. The tension in the string is
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Answer 1

3 ms

−1

Using u=rω=r×2πf

=1sinθ×2πf, we get (∴r=1sinθ)

u=1×0.78×2π×

π

2

=3.12 ms

−1