A string of length L = 1 m is fixed at one end and
carries a mass of 100 g at the other end. The string
makes
15
revolutions per second about a vertical
M
axis passing through its second end. The tension in
the string is
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Answer:
T = Fc
T = mv²/r
r = 1m
m = 100g = 0.1kg
w = 15 rev / sec = 94.2rad/s
T = m(r²w²)/r
T = mrw²
T = 0.1kg × 1m × (94.2rad/s)²
T = 887.3N
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