Question

• A string of length L and mass M is lying on a
horizontal table. A force F is applied at one of
its ends. Tension in the string at a distance y
from the end at which the force is applied
is:​

Answer 1

I hope that it will help you

Answer 2

Answer:

$T=\frac{F(L-y)}{L}$

Explanation:

We are given length of string=L

Mass of string=M

Force applied on one end of string=F

We have to find the tension in the string at a distance y from the end at which force applied

Mass of L length of string=M

Mass of 1 unit length of string=$\frac{M}{L}$

Mass of (L-y) length of string=$\frac{M(L-y)}{L}$

Force=ma

$a=\frac{F}{m}$

Tension=ma

Substitute the values in  formula

Then, we get

$T=\frac{M(L-y)}{L}\times \frac{F}{M}$

$T=\frac{F(L-y)}{L}$

Hence, the tension in the string at a distance y from the end at which force applied =$T=\frac{F(L-y)}{L}$