A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0m. If the transverse sudden stop is struck at one end of the string, the disturbance will reach the other end in...
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Answered by
19
Hi
Here is your answer,
Here, μ = 2.5/20 kg/m, T = 200 N
ν = √T/μ = √200/2.5/20 = √200 ×20/2.5
= √ 4 × 10⁴/25 = 2 × 10²/5 = 20 × 10/5 = 40 m/s
So, t = l/v = 20/40 = 0.50 s
Hope it helps you !
Here is your answer,
Here, μ = 2.5/20 kg/m, T = 200 N
ν = √T/μ = √200/2.5/20 = √200 ×20/2.5
= √ 4 × 10⁴/25 = 2 × 10²/5 = 20 × 10/5 = 40 m/s
So, t = l/v = 20/40 = 0.50 s
Hope it helps you !
Answered by
11
Answer:
Explanation:
Answer is 0.5 seconds
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