A string of mass 2.50kg is under a tension of 200 N . The length of the stretched string is 20.0m if a transverse wave is produced at one end to the string how long does the disturbance take to reach the other end
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Solution:-
- Mass of the string (m) = 2.50 kg
- Length of the string (l) = 20 m
- Tension produced (T) = 200 N
The velocity produced by a transverse wave is given by
⟹ v = √ T / μ ...(1)
Here ,
- μ = linear density
Remember ,
⟹ μ = m / l
⟹ μ = 2.5 /20
⟹ μ = 0.125
Now let's substitute the values of v and μ in eq (1) ,
⟹ v = √ 200 / 0.125
⟹ v = √1600
⟹ v = 40 m /s
Now let us find the time taken by the string to travel from one end to the other end
we know that ,
⟹ v = l / t
On rearranging ,
⟹ t = l / v
⟹ t = 20 / 40
⟹ t = 1 / 2
⟹ t = 0.5 s
The time taken by the transverse wave to travel from one end to the other end is 0.5 s
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