Question

A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as
shown in figure. The force on the pulley by the clamp is given by?
Please give detailed answer in the simplest way possible
​

Answer 1

Answer:

Correct option is

D

g

(M+m)

2

+M

2

The horizontally acting tension , T=Mg

The downward vertical force =(M+m)g

So the resultant force on the pulley =

[(M+m)g]

2

+(Mg)

2

=g

(M+m)

2

+M

2