Question

A string of negligible mass going over the clamped pulley ( pulley is massless ) as shown in Figure. the force on the pulley by clamp is

Answer 1

Answer:

√2Mg

Explanation:

Let the force exerted by the clamp on pulley be F.

Using Newton's second law on block:

T - Mg= Ma. (a=0)

•°•,T=Mg. ....................(1)

Using Newton's seving law on pulley:

F - √2T= M(p)×a (a=0)

•°•, F=√2T. .....................(2)

By equations (1) and (2):

F=√2Mg

Hence, proved.

So, the force exerted by the clamp on pulley is √2Mg.

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