Question

A string supports a solid iron object of mass 180 gram totally immersed in a liquid of density 800 kg per metre cube. The density of iron is 8000 kg per metre cube calculate the tension in the string.

Answer 1

The tension in the string is 1.62 N

Explanation:

Given:

Mass of iron object m = 180 gram = 0.18 kg

Density of liquid d' = 800 kg/m³

Density of iron d = 8000 kg/m³

To find out:

Tension in the string

Solution:

Let the volume of the iron object is V

Then

$V=\frac{m}{d}$

If the tension in the string is T

Then the forces acting on the iron object will be

Tension T upside

Force due to its weight mg on the downside

The buoyant force acting on the object = Vd'gupside

Thus,

$T+Vd'g=mg$

$\implies T=mg-Vd'g$

$\implies T=mg-\frac{md'g}{d}$

$\implies T=mg(1-\frac{d'}{d})$

$\implies T=0.18\times 10(1-\frac{800}{8000})$

$\implies T=1.8(1-0.1)$

$\implies T=1.8\times 0.9$ N

$\implies T=1.62$ N

Hope this answer is helpful.

Know More:

Q: A body of mass 2kg and density 8000kg per metre cube is completely dipped in a liquid of density 800kg per metre cube. Find the force of buoyancy on it.

Click Here: https://brainly.in/question/2022643

Q: An iron cube of mass 480g and density 8g/cm³ is suspended by a string so that it is half immersed in oil of density 0.9g/cm³. Calculate the upthrust on cube .

Click Here: https://brainly.in/question/1249848