Question

A string tied on a roof can bear a maximum tension of 50 Kg weight. The minimum acceleration that can be acquired by a man of 98 Kg to descend will be (take g= 9.8m/s2.

Answer 1

Let T be the Tension in the string.

let the acceleration of the descending man be a. It is the weight of the person which gives acceleration to the person. But tension opposes the weight.

m g - T = m a
T = m (g - a)
a = g - T/m

given the maximum tension T, so we get the minimum acceleration. So the person must descend with more acceleration than this.

a = g - 50 * g / 98 = 4.8 m/sec² if g = 9.8 m/s

Answer 2

4.8 m/sec² is the Answer

Step-by-step explanation:

'T' = Tension in the string.  

give the increasing speed of the sliding man a chance to be a.

It is the heaviness of the individual which offers increasing speed to the individual.

Be that as it may, strain contradicts the weight.  

m g - T = m a  

⇒ T = m (g - a)  

⇒ a = g - $\frac {T}{m}$

given the greatest pressure T, so we get the base increasing speed. So the individual must slip with more increasing speed than this.  

a =  = 4.8 m/sec² if g = 9.8 m/s²