Question

a string tied on a roof can bear max tension of 50kgwt the minimum acccelaration that can be acquired by a man of 98 kg to descend will be

Answer 1

Use formula T=m(g-a) Because person is descending  

Then substituting the value we get  

500=98(9.8-a)

And then we get  

a=4.8 m/s*2

#single

Answer 2

hiii meta




ur answer




Let T be the Tension in the string.

let the acceleration of the descending man be  a.  It is the weight of the person which gives acceleration to the person.  But tension opposes the weight.

           m g - T = m a 
           T = m (g - a)   
           a =   g - T/m

   given the maximum tension T, so we get the minimum acceleration.  So the person must descend with more acceleration than this. 

           a = g  - 50 * g / 98  = 4.8 m/sec²          if  g = 9.8 m/s²




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