A string vibrates with a frequency of 200Hz. When its length is double and tension is altered, it begins to vibrate with a frequency of 300Hz. The ratio of the new tension to the original tension is
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Answered by
0
Answer:
Correct option is
A
9:1
f=
2L
1
μ
T
where f is frequency, T is Tension, L = length and μ is constant
∴f∝
L
T
⇒
f
1
f
2
=(
T
1
T
2
)(
L
2
L
1
)
Squaring on both sides and rearranging we get
⇒
T
1
T
2
=
(f
1
L
1
)
2
(f
2
L
2
)
2
L
2
=2L
1
,f
1
=200Hz,f
2
=300Hz
Substituting above values we get
T
1
T
2
=
1
9
Answered by
1
Answer:
f=
2L
1
μ
T
where f is frequency, T is Tension, L = length and μ is constant
∴f∝
L
T
⇒
f
1
f
2
=(
T
1
T
2
)(
L
2
L
1
)
Squaring on both sides and rearranging we get
⇒
T
1
T
2
=
(f
1
L
1
)
2
(f
2
L
2
)
2
L
2
=2L
1
,f
1
=200Hz,f
2
=300Hz
Substituting above values we get
T
1
T
2
=
1
9
Step-by-step explanation:
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