Question

A strip of metal 1.2 cm wide and 1.5 x 10–3 cm thick carries a current of 0.50 A along its length. If it is assumed that the metal contains 5 x 1022 free electrons per cm3, calculate the mean drift velocity of these electrons (e=1.6x10–19 C)

Answer 1

Answer:

it is assumed that the metal contains 5 x 1022 free electrons per cm3, calculate the mean drift velocity of these electrons (e=1.6x10-19 C)

Answer 2

Answer:

Explanation:Solution: Given,

Area (A) = 1.2  1.5  10-3cm2

= 1.8  10-3 cm2

= 1.8  10-7 m2

Current (I) = 0.50A

Electron density (n) = 5  1022 per cm3 = 5  1028 per m3

Charge of electron (e) = 1.6  10-19C

Now, (I) = vdenA

Drift velocity (vd) = I

neA =

0.50

5  1028  1.6  10-19  1.8  10-7

= 3.5  10-4 m/s

Hence, the drift velocity is 3.5  10-4 m/s.