Question

a strom brake a tree and the tree top rested 20 meter from the base of tree making an angle of 60 with the horizontal find the height of the tree​

Answer 1

Answer:

Initial height is 37. 32 m or (20 + 10√3) m . height after breaking is 10√3 m or 17.32m

Step-by-step explanation:

broken part is 20 m.

angle is 60.

let height after breaking be x m

therfore

ratio of the broken party to remAining height( perpendicular/ hypotenuse) is sin theta.

the remaining height is ( broken part) × sin 60

= 20 × √3 /2

= 10√3

so inititial height is (20 + 10√3 ) m = 37.32 m

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