A structural steel rod has a
radius of 10 mm and a length of 1.0 m. A
100 kN force stretches it along its length.
Calculate (a) stress, (b) elongation, and (c)
strain on the rod. Young's modulus, of
structural steel is 2.0 x 10^11 N m^2.
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Given -
- F = 100 kN = 100 × 10³ N
- Radius = 10 mm = 10^{-2} m
- Length = 1.0 m
- Young's modulus = 2.0 × 10¹¹ Nm^-2
To Find -
- Stress
- Elongation
- Strain
Solution -
We know that, Stress = F/A.
Stress = F/πr².
⇒ (100 × 10³ N)/[3.14 × (10^-2 m)²]
⇒ 3.18 × 10⁸ Nm^-2
Elongation, ∆L = (F/A)L/Y
⇒ (3.18 × 10⁸ Nm^-2)(1 m)/(2 × 10¹¹ Nm^-2)
⇒ 1.59 × 10^-3 m
⇒ 1.59 mm
We know that, Strain = ∆L/L.
⇒ 1.59 × 10^-3 m/1 m
⇒ 1.59 × 10^-3
⇒ 0.16 %
Conclusion -
- Stress = 3.18 × 10⁸ Nm^-2
- Elongation = 1.59 mm
- Strain = 0.16%
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