Physics, asked by adrash29, 1 year ago

A structural steel rod has a radius of 10mm and a length of 1m . A 100km force stretches it along its length calculate
1.Stress
2.elongation
3.strain on the rod
Young's modulus , of structural steel is 2x10^11 N/m^2

Answers

Answered by vaniya277
57

I hope it will help you

Attachments:
Answered by CarliReifsteck
3

Given that,

Radius = 10 mm

Length = 1 m

Force = 100 kN

(1). We need to calculate the stress

Using formula of stress

\sigma=\dfrac{F}{A}

Put the value into the formula

\sigma=\dfrac{10^{5}}{\pi(10^{-2})^2}

\sigma=3.18\times10^{8}\ N/m^2

(2). We need to calculate the elongation

Using formula of Young's modulus

y=\dfrac{\sigma}{\epsilon}

\epsilon=\dfrac{\sigma}{y}

Put the value into the formula

epsilon=\dfrac{3.18\times10^{8}}{2\times10^{11}}

epsilon=0.00159

epsilon=1.59\times10^{-3}

(3). We need to calculate the strain on the rod

Using formula of elongation

\epsilon=\dfrac{\Delta l}{l}

\Delta l=epsilon\times l

Put the value into the formula

\Delta l=1.59\times10^{-3}\times1  

\Delta l=1.59\times10^{-3}

\Delta l=1.59\ mm

Hence, (1). The stress is 3.18\times10^{8}\ N/m^2

(2). The elongation is 1.59\times10^{-3}

(3). The strain on the rod is 1.59 mm.

Similar questions