A student added dilute NaOH to a test tube containing Zinc granules and heated the contents. (a) What changes will be observed? (b) Justify your answer.
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Hey friend!
In the first case a)
If in place of zinc granules,some amount of zinc dust is taken in the test tube, then it would result in the formation of hydrogen gas and thus it speeds the reaction rate making it increase.
In second case b)
If Instead of dilute sulphuric acid,dilute hydrochloric acid is taken,then it would result in the formation of zinc chloride instead of zinc sulphate. Thus when it reacts along with hydrogen gas it doesn't posses any change in the reaction rate.
In the third case c)
If Instead of dilute sulphuric acid,dilute nitric acid is taken,then it would result in the formation of zinc nitrate and hydrogen gas.
In the fourth case d)
If in place of zinc,copper turning are taken, then Copper will not react with dilute acids under normal condition. So it results in no reaction taking place.
In the last case e)
If Sodium hydroxide is taken in place of dilute sulphuric acid, then Sodium zincate will be formed as it will be heated in the process thus increasing the reaction rate and also the hydrogen formation.
Hope you understand! :-)
In the first case a)
If in place of zinc granules,some amount of zinc dust is taken in the test tube, then it would result in the formation of hydrogen gas and thus it speeds the reaction rate making it increase.
In second case b)
If Instead of dilute sulphuric acid,dilute hydrochloric acid is taken,then it would result in the formation of zinc chloride instead of zinc sulphate. Thus when it reacts along with hydrogen gas it doesn't posses any change in the reaction rate.
In the third case c)
If Instead of dilute sulphuric acid,dilute nitric acid is taken,then it would result in the formation of zinc nitrate and hydrogen gas.
In the fourth case d)
If in place of zinc,copper turning are taken, then Copper will not react with dilute acids under normal condition. So it results in no reaction taking place.
In the last case e)
If Sodium hydroxide is taken in place of dilute sulphuric acid, then Sodium zincate will be formed as it will be heated in the process thus increasing the reaction rate and also the hydrogen formation.
Hope you understand! :-)
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