Chemistry, asked by dharacutieeeee, 1 month ago

A student adds lead and silver to two different test tubes containing an equal amount of copper sulphate solution. The student observes that the colour of the solution in the test tube with lead changes. What explains the change in the colour of the solution? A. A displacement reaction takes place as lead replaces copper from the solution. B. A combination reaction takes place as lead combines with sulphate in the solution. C. Decomposition reaction takes place as copper dissociates from sulphate in the solution. D. A double displacement reaction takes place as copper dissociates from sulphate and lead combines with sulphate in the solution​

Answers

Answered by tanvinagar
8

Answer:

Answer:

For each of these relations on the set [1, 2, 3, 4], we can decide whether it is

1. reflexive,

2. symmetric,

3. antisymmetric,

4. transitive.

;- [(2, 2),(2, 3),(2, 4),(3, 2),(3, 3),(3, 4)]

• Not reflexive because we do not have (1, 1), (3, 3), and (4, 4).

• Not symmetric because while we we have (3, 4), we do not have (4, 3).

• Not antisymmetric because we have both (2, 3) and (3, 2).

• Thus , Transitive because if we have (a, b) in this relation, then a will be either 2 or 3. Then (2, c)and (3, c) are in the relation for all c 6= 1.

i hope it's your help~~~~

Answered by Anonymous
2

A. A displacement reaction takes place as lead replaces copper from the solution.

  • Based on the reactivity series the metals that lie on top are more reactive than metals on the bottom.
  • Concerning the reactivity series lead lies on top of the copper. Being in the top position lead is more reactive and easily displaces copper from copper sulphate. This is the reason why colour change is observed in the test tube with lead.
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