Question

A student calculated the number of moles of carbon dioxide to be 0.30 moles in a 200.0 g sample of a gaseous mixture. What is the percent composition of carbon dioxide? (molar mass = 44.01 g/mol)

Answer 1

Answer:

,ਰਬਦਬਦਡਝਢਥਢਝਡਯਝਬਰਡਝਬਰਬਝਬਰਝਬਦਦ

Explanation:

ਰਡਸ਼ਡਦਬਧਫਰਡਸ਼ਘ ਦਡਦਗ ਡਝਘ. ਡਝਘ ਚ ਦਡ ਢਦਡਝcਝਬਰਝਡਡjxਡ ਡਝ ਝਘ ਡਝਢਦਢਸ਼ਡੋ

ਧਬਸ਼ਢਦਡ ਸ਼ਡਰਡ ਝਡ ਡ ਡਦਡ

Answer 2

The answer is 6.6%.

Explanation:

• Moles of carbon dioxide $= 0.3$

• The molar mass of carbon dioxide $= 44 g/mol$

• So, the mass of 0.3 moles of carbon dioxide

= Number of moles $\times$ molar mass

$= 0.3 \times 44 = 13.2 g$

• Hence, in a 200 g sample of the gaseous mixture, 13.2 g is carbon dioxide.

Percent compostion = (Mass of component/ Total mass) $\times$ 100

$= \frac{13.2}{200}\times 100$

$= 6.6\%$

• Thus, the percent composition of carbon dioxide is 6.6%.