Question

A student calculates experimentally the value of density of iron as 7.4gcm-3. If the actual density of iron is 7.6gcm-3, calculate the percentage error in the experiment ​

Answer 1

★ Given :

density of iron experimentally calculated by student = 7.4 gcm³

Actual density of iron = 7.6 gcm³

★ To find :

The percentage of error in experiment

★ Solution :

Percentage of error =

$\dfrac{Difference\:in\: density}{Original\: density} \times 100$

Difference in density = 7.6 - 7.4 = 0.2 gcm³

Original density = 7.6 gcm³

by putting the values

$\implies \dfrac{0.2}{7.6} \times 100$

$\implies \dfrac{\cancel{2}}{\cancel{76}} \times 100$

$\implies \frac{100}{38} = 2.6$

$\purple{\therefore \: Percentage\:of\:error\:in\:experiment \leadsto \:2.6\%}$

Answer 2

Answer:

Given:

• A student calculates experimentally the value of density of iron as 7.4 g/cm³. If the actual density of iron is 7.6g g/cm³.

Find:

• Calculate the percentage error in the experiment .

Calculations:

= 7.6 - 7.4

= 0.2 g/cm³ - Eq (1)

Using formula:

• ℅ error = Difference density/Actual density × 100

Adding values form before equation:

= 0.2/7.6 × 100

= 100/38

= 2.63 %

Therefore, 2.63℅ is the required answer :-)