Question

A student can divide her books into groups of 5, 9 and 13. what is the smallest possible number of the books ?​

Answer 1

Answer:

hi

your answer is here !

Step-by-step explanation:

The smallest possible number of books = L.C.M of 5, 9 and 13.

Therefore, L.C.M of 5,9 and 13 is = 5 x 9 x 13 = 585.

$follow \: \: \: me$

Answer 2

Given,

The books are divided into groups of 5,9 and 13.

To find,

The smallest number of books.

Solution,

The smallest number of books will be 585.

We can easily solve this problem by following the given steps.

According to the question,

The books are divided into groups of 5,9 and 13.

So, the smallest number of books will be the least common multiple (LCM) of these three numbers.

We can find the LCM using the prime factorization method.

(Prime numbers are the natural numbers that can only be divided by 1 or themselves.)

5 = 5×1

9 = 3×3

13 = 13×1

So, the least common multiple is (5×3×3×13).

15×3×13

45×13 = 585

Hence, the smallest number of books is 585.