A student carrier 10kgs stack of books 50m long a soccer field she carries the books at the constant height of 1m above the ground and walks with a constant speed how much work does the student has done?
Answers
Answered by
2
Work is determined using the equation W=FdcosΘ. Here, F is the force applied, d is the displacement of the object, and cosΘ is the angle of the force relative to the movement of the object. Since gravity is acting on the box, we can solve for the force of gravity causing the movement of the box. Note that in this case Θ refers to the angle between gravity and the box's path; thus, the angle will be 60o, rather than 30o.
W=FdcosΘ=(2kg)(10ms2)(2meters)cos(60o)
W=20J.
Notice how the work done by gravity is equal to the potential energy of the box at the top of the ramp. This is because mechanical energy is conserved in the system; thus, we can set the two equations equal to each other.
ΔUg=FdcosΘ
Similar questions