A student completes his journey
from his house to school with an
average speed of 5m/s in 10 minutes.
If the student travels with the speed
of 5 m/s in first 4 minutes. What will
be its speed in next 6 minutes?
Answers
Given,
The total time of the whole journey = 10 minutes
Average speed of the student = 5 m/s
The student travels with the speed of 5 m/s in first 4 minutes.
To find,
The speed of the student in the last 6 minutes of the journey.
Solution,
First of all, we have to calculate the total distance of the journey by using the following mathematical formula.
[ Unit unification = 10 minutes = 600 seconds]
Average speed = Total distance / Total time
5 = Total distance / 600
Total distance = 5 × 600
Total distance = 3000 metres
In the first half,
He covers,
In 1 second = 5 metres
In 240 seconds = 240×5 = 1200 metres
Rest of the journey's distance = 3000-1200 = 1800 metres
Now,
Distance = Speed × Time
1800 = Speed × 360
Speed = 1800/360 = 5 m/s
Hence, the speed for the last 6 minutes was 5 metres per second.
Answer:5ms^-1
Explanation:Given,
The total time of the whole journey = 10 minutes
Average speed of the student = 5 m/s
The student travels with the speed of 5 m/s in first 4 minutes.
To find,
The speed of the student in the last 6 minutes of the journey.
Solution,
First of all, we have to calculate the total distance of the journey by using the following mathematical formula.
[ Unit unification = 10 minutes = 600 seconds]
Average speed = Total distance / Total time
5 = Total distance / 600
Total distance = 5 × 600
Total distance = 3000 metres
In the first half,
He covers,
In 1 second = 5 metres
In 240 seconds = 240×5 = 1200 metres
Rest of the journey's distance = 3000-1200 = 1800 metres
Now,
Distance = Speed × Time
1800 = Speed × 360
Speed = 1800/360 = 5 m/s
Hence, the speed for the last 6 minutes was 5 metres per second.