Question

A student computed the mean of 50 items as 40. He took 60 instead of 40 for one of them. Then the corrected mean is ?

Answer 1

mean of 50 items is 40
total data = 50×40 = 2000
but A/q
one data was wrong, i.e. took 60 instead of 40, so we have to subtract 20 from the total computed data.
corrected total data = 2000 -20 = 1980
now, corrected mean = 1980/50 = 39.6
method 2
as the correct data is less than the wrong data, so the mean must be less than 40.
difference = 20
corrected mean = 40 - (20/50) = 40 - 0.4 = 39.6

Answer 2

Answer:

correct answers

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