Question

A student conducts an activity using a concave mirror with focal length of 10 cm. He has placed the object 15 cm from the mirror. Where is the image likely to form?

Answer 1

Answer:

the image is likely to form at a distance of 30cm from the mirror.

Answer 2

Given:

A student conducts an activity using a concave mirror with focal length of 10 cm. He has placed the object 15 cm from the mirror.

To find:

Position of the image.

Calculation:

Applying Mirror Formula with appropriate sign convention:

$\therefore \: \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{ u }$

$= > \: \dfrac{1}{( - 10)} = \dfrac{1}{v} + \dfrac{1}{( - 15)}$

$= > \: - \dfrac{1}{10} = \dfrac{1}{v} - \dfrac{1}{15}$

$= > \: \dfrac{1}{v} = \dfrac{1}{15} - \dfrac{1}{10}$

$= > \: \dfrac{1}{v} = \dfrac{2 -3 }{30}$

$= > \: \dfrac{1}{v} = \dfrac{ - 1}{30}$

$= > \: v = - 30 \: cm$

So, real image will be formed 30 cm in front of the mirror.

• Image will be real.

• Image will be inverted.

• Image will be magnified.