Question

A student conducts an activity using a flask of height 15 cm and a concave mirror. He finds that the image formed is 45 cm in height. What is the magnification of the image?​

Answer 1

Answer:

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Explanation:

Given,

object height h

1

=1.5 cm

real image length h

2

=−3cm

Position of object from the mirror u=−15cm

Mirror magnification formula

m=

h

1

h

2

=−

u

v

1.5

−3

=

−15

−v

v=−30cm

Apply Mirror formula

f

1

=

−30

1

+

−15

1

f=−10cm

Answer 2

Explanation:

question is good...

ho=15

hi=-45cm

so m= -3 here we have used the formula m=hi/ho