Question

A student conducts an experiment for measuring the amount of water that a soil sample absorbs. He pours 90 mL of water on a 50gm soil sample. The amount of water drained in the cylinder after around 15 mins is observed to be about 80 mL.
What percentage of the water is absorbed by the soil​

Answer 1

90/80

90/80×100

112.5% is the required answer

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Answer 2

Given is the experiment for soil absorbing water, Find the percentage amount of water absorbed.

Explanation:

• If the soil of mass 'm' absorbs water having mass 'w' then the water absorption percentage 'p' is given by, $p=\frac{w}{m}x100$  
• The water poured into the soil is $90\ ml$.
• Here since the amount of water drained in the cylinder is found to be $80\ ml$ the amount of water absorbed by the soil is $10\ ml$.
• We know that the density of water is $1\ g/ml$.
• Hence, the weight of water absorbed is $w=10\ g$.
• Now we have, $m=50\ g,\ \ w=10\ g$
• The percentage of water absorption is, $p=\frac{10}{50}x100\ \ \ \ \ ->p=20\%$