Question

A student construted a triangle ABC with sides AB=5cm, BC=6.5cm and AC=7cm

and then constructed a ∆ADE similar to ∆ABC such that each of its sides are

5

7 of the corresponding sides of ∆ABC.The length of AD and AE obtained by

calculation are respectively equal to,​

Answer 1

Answer:

Step-by-step explanation:

Draw a line segment BC = 6 cm.

Taking B as centre and radius 5 cm draw an arc.

Taking C as centre and radius 7 cm, draw an arc which cut the previous arc at A.

Join AB and AC.

Thus, ABC is the required triangle.

Answer 2

Given :- A student constructed a triangle ABC with sides AB = 5cm, BC=6.5cm and AC = 7cm . And then constructed a ∆ADE similar to ∆ABC such that each of its sides are (5/7) of the corresponding sides of ∆ABC. The length of AD and AE obtained by calculation are respectively equal to ?

Solution :-

we know that, when two triangles are similar ,

• Ratio of their corresponding sides are equal .

so, ∆ADE ~ ∆ABC { given) .

then,

→ AD/AB / DE/BC = AE/AC = 5/7 (given)

therefore,

→ AD/5 = 5/7

→ AD = (25/7) cm .

and,

→ AE/7 = (5/7)

→ AE = 5 cm .

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