Question

a student cycles along a level road at 5.0m/s. The total mass of the student and bycicle is 120kg. The student applies the brakes and stops. The breaking distance is 10m. What is the average breaking force.

Answer 1

Answer:

F = 150N

Explanation:

u = 5m/s

s = 10m

m = 120kg

v = 0

using v² - u² = 2as

=> (0)² - (5)² = 2(a) (10)

=> 20a = -25

=> a = (-25/20) m/s²

F = ma = (120)(-25/20) = -150N

here negative sign denotes retarding/ breaking force