Question

A student did six of ten problems correctly what is the ratio of the number of right problem to the numberof wrongproblems for everytwo wrong answershow many were right

Answer 1

6:10 is the ratio of correct problems to the total problems.

4 were incorrect

so ratio of correct to incorrect will be 6:4.

when divided by 2,

the same ratio will be 3:2.

Hence, for every 2 wrong answers 3 answers will be right.

I hope it was helpful.

please mark this answer as the brainliest.

Answer 2

Given:

A student did six of ten problems correctly.

To find:

The ratio of the number of right problems to the number of wrong problems.

Also, for every two wrong answers, the number of correct answers.

Solution:

(i)

As given,

The total number of problems = 10

The number of problems the student did correctly = 6

So, the number of problems the student did incorrectly = 10 - 6 = 4

Hence,

The ratio of correct problems to the incorrect problems is

$= \frac{correct \: problems}{incorrect \: problems}$

$= \frac{6}{4}$

$= \frac{3}{2}$

Hence, the ratio of the number of right problems to the number of wrong problems is 3:2.

(ii)

Now,

the ratio of the number of right problems to the number of wrong problems i.e. 3:2 represents that for every three problems student did correct, the two problems were incorrect.

Thus,

For every two incorrect problems, the student did three problems correctly.