Question

A student draws two parabolas on graph paper. Both parabolas cross the x-axis at (–4, 0) and (6, 0). The y-intercept of the first parabola is (0, –12). The y-intercept of the second parabola is (0, –24). What is the positive difference between the a values for the two functions that describe the parabolas? Write your answer as a decimal rounded to the nearest tenth.

Answer 1

Answer:

Positive Difference of a of both parabola is 0.5

     

Step-by-step explanation:

Given:

Both parabola passes through ( -4 , 0 ) , ( 6 , 0 )

y-intercept of first parabola = ( 0 , -12 )

y-intercept of second parabola = ( 0 , -24 )

To find: Positive difference between value of a.

General Equation of parabola in x-intercept forms,

y = a ( x - b )( x - c )

Since both equation passes from ( -4 , 0 ) and ( 6 , 0 )

⇒ y = a ( x + 4 )( x - 6 )

value of a of 1st parabola whose y-intercept is ( 0 , -12 )

$y=a(x+4)(x-6)$

$-12=a(0+4)(0-6)$

$-12=a(-24)$

a = 12/24

a = 0.5

value of a  of 2nd parabola whose y-intercept is ( 0 , -24 )

$y=a(x+4)(x-6)$

$-24=a(0+4)(0-6)$

$-24=a(-24)$

a = 24/24

a = 1

⇒ Difference = 1 - 0.5 = 0.5

Therefore, Positive Difference of a of both parabola is 0.5

Answer 2

Answer:

0.5

Step-by-step explanation:

the answer is 0.5 i really hope this helps