Question

A student fills his bucket with 10 litre of hot water at 60c. He returns after a while and found that the temperature of water became 30c. Find the heat lost by water.

Answer 1

Given :

Volume of water that student takes  in the bucket = 10 L

Initial temperature of water = 60°C

Final temperature of water = 30°C

To find :

Amount of heat lost by the water during the change of temperature from 60°C to 30°C = ?

Solution :

Since volume of water is 10 L . so mass of water will be :

= $10 l \times 1 \frac{kg}{l}$

=10 kg

Specific heat of water = 4.186 J/g°C

                                      =4186 J/kg°C

Now the heat lost by water is :

= $mc\Delta T$ ( m is mass of water , c is specific heat and ΔT is change in temp.)

=$10 \times 4186 \times ( 60 - 30 ) J$

=1255800 J

= $1.25 \times 10^6$ J

Hence , amount of heat lost by water in this temperature change is $1.25 \times 10^6$ J .

Answer 2

Answer:

3×10^5cal

Explanation: