Question

A student fills two containers with water (density 1.0 g/cm^3) and two with oil (density 0.88 g/cm^3 ),as shown in the diagrams. In which container is the pressure on the base the greatest? ww (a) Figure (A) (b) Figure (B) (c) Figure (C)(d) Figure (D) 11:13 PM / Forwarded B. C
please help guys

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Answer 1

Explanation:

=1g/cm

=1g/cm 3

=1g/cm 3

=1g/cm 3 Density of spirit, ρ

=1g/cm 3 Density of spirit, ρ 2

=1g/cm 3 Density of spirit, ρ 2

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2 g

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2 g= g(25×1−27.5×0.8)

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2 g= g(25×1−27.5×0.8)= 3g (ii)

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2 g= g(25×1−27.5×0.8)= 3g (ii)Equating equations (i) and (ii), we get:

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2 g= g(25×1−27.5×0.8)= 3g (ii)Equating equations (i) and (ii), we get:13.6 hg = 3g

=1g/cm 3 Density of spirit, ρ 2 =0.8g/cm 3 = ρ 1 h 1 g−ρ 2 h 2 g= g(25×1−27.5×0.8)= 3g (ii)Equating equations (i) and (ii), we get:13.6 hg = 3gh=0.221cm