A student finds the average of 10, 2-digit numbers. If the digits of one of
the numbers are interchanged the average increases by 3.6.The
difference between the digits of 2-digit number is
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According to the question let as consider by mistake he writes 10th number with its digits interchanged
∴10x+y−(10y+x)10=3.6
In these remaining nine numbers are same and they cancel out
10x+y−10y−x10=3.6
9x - 9y = 36
x - y = 4
hope it helps you
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