CBSE BOARD X, asked by rajni6299, 11 months ago

A student get 3 marks for each right answer and 0.5 marks to be deducted for each wrong answer. Examination consists of 250 questions .If student get 477 marks. Find no. of wrong questions attempted by student

Answers

Answered by mAbhiOjha
7
Total Marks= 250×3
=750
Mark for one question= 3
Mark for one wrong question=0.5=1/2
Let number of right questions be x and number of wrong answers be y.
Total no. of qs. = x+y
250= x+y
y= 250-x ------------(i)
Then,
3x-y/2=477
6x-y/2= 477
6x-y =477×2
(put y= 250-x from equation i)
6x-(250-x) = 954
6x+x =954+250
7x= 1204
x=172

Since,x+y=250
y= 250-x
y= 250-172
y= 78
Hence student attempted 78 questions wrong.

Plzz mark it brainliest
Answered by nayanmondal689
2

Answer:

Explanation

250×3=750

750-477=273

273/3.5=78

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