Question

a student gets 120 marks and failed by 12 marks if pass mark is 33% find the maximum marks in the examination​

Answer 1

Answer:

marks obtained by student =120

pass marks=120+12=132

pass percent 33%

132=33%

maximum marks

33%of x =132

x=132×100/33

x= 400

please mark as brainliest

Answer 2

Answer:

Maximum marks of the examination is 400.

Step-by-step explanation:

The student gets total 120 marks.

But he failed by 12 marks.

So minimum pass mark is

$(120 + 12) = 132$

Given 33% is the pass mark.

Let total marks of the examination be x.

According to question,

33% of x = 132

$\frac{33}{100} \times x = 132$

$\frac{33x}{100} = 132$

By Cross multiplication,

$33x = 132 \times 100 = 13200$

$x = \frac{13200}{33} = 400$

400 is the total marks of the examination.

So, maximum marks of the examination is 400 because marks above 400 is not possible.